Question

If each diode in Fig. 14.13 has a forward bias resistance of 25Ω and infinite resistance in reverse bias, what will be the values of the current I₁, I₂, I₃ and I₄?

Answer 1

I₃ is zero as the diode in that branch is reverse bised. Resistance in the branch AB and EF are each (125 + 25)Ω = 150Ω.

As AB and EF are identical parallel branches, their effective resistance is 150/2=75Ω

Net resistance in the circuit = (75 + 25) Ω = 100Ω .

Current I₁=5/100=0.05A.

As resistances of AB and EF are equal, and I₁ = I₂ + I₃ + I₄, I₃ = 0

I₂=I₄=0.05/2=0.025A