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The line x + y = 2 is tangent to the curve x2 = 3 - 2y at its point

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1 Answer

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x2 = 3 – 2y

2x = 0 – 2 (dy / dx)

⇒ dy / dx = – x

The slope of the tangent of the curve is -x.

From the given information of the line, the slope is -1.

So, x = 1 and y = 1.

The required point is (1, 1).

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