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1. Write any one use of capacitor 

2. Obtain an expression for capacitance of a parallel plate capacitor

3. The Capacity of a parallel plate capacitor becomes 10µF when air between the plates is replaced by a dielectric slab (k = 2). What is the capacity of the capacitor with air in between the plates?

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1. one use of capacitor:

  • Capacitor is used to store electric charges
  • It is used to prevent dc current.

2. Expression for capacitance of a capacitor: Potential difference between two plates V = Ed

\(\frac{\sigma}{\varepsilon_0}d\)      (∴\(E=\frac{\sigma}{\varepsilon_0}\))

V = \(\frac{Q}{A\varepsilon_0}d\) ..........(1)  \((σ=\frac{Q}{A})\)

Capacitance C of the parallel plate capacitor,

C = \(\frac{Q}{V}\) ...........(2)

Sub eq. (1) in eq. (2)

C = \(\frac{Q}{\frac{Q}{A\varepsilon_0}d}\)

C = \(\frac{A\varepsilon_0}{d}\)

3. C = 10µF

When dielectric slab is placed, New capacitance

C1 = KC

10 × 10-6 = 2 × C, C = 5 × 10-6 F.

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