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A battery of e.m.f. 10 V and internal resistance 3 W is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?

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Given E = 10 V, r = 3?, I = 0.5, R = ?

Since V = E – Ir

or V = 10 – 0.5 × 3

or V = 8.5 volt

And R = \(\frac{V}{I}\) = \(\frac{8.5}{0.5}\) = 17 A

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