1. ρ = \(\frac{RA}{l}\)
2. Temperature and Nature of metal
3. We know current density
J = nvde
But Vd = \(\frac{eE}{m}\tau\)
∴ \(\bar J=n.\frac{e\overrightarrow E}{m}\tau e\)
\(\bar J=\frac{ne^2}{m}\tau \overrightarrow E\)
\(\bar{J}=\sigma\overrightarrow E\) where \(\sigma = \frac{ne^2}{m}\tau\)
But ρ = \(\frac{1}{\sigma}=\frac{m}{ne^2\tau}\)
4. When temperature increases, the amplitude of oscillation of atom increases. This will decrease . the relaxation time and hence resistivity increases.