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+1 vote
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in Moving Charges and Magnetism by (26.2k points)
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A uniform field equal to 1.5 T exists in a cylindrical region of radius 10.0 cm, its direction parallel to the axis along east to west. A wire carrying current of 7.0 A in the north to south direction passes through this region. What is the magnitude and direction of the force on the wire if

1. The wire intersects the axis?

2. The wire is turned from N-S to north east north west direction.

3. The wire in the N-S direction is lowered from the axis by a distance of 4.0 cm?

1 Answer

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by (26.7k points)
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Best answer

1. F = B1l = 1.5 × 7 × \(\frac{20}{100}\)  or F = 2.1 N acting vertically downwards. 

2. Force will again be 2.1 N.

3. F = \(\frac{1.5\times7\times16}{100}\) = 1.68 N

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