1. force and torque
2. When the bar magnet is perpendicular to the field Torque is maximum
τ = MBsinθ = MBsin(90) = MB
When rotated through an angle θ, torque is
\(\frac{\tau}{4}\) = MB sinθ
\(\frac{\tau}{\frac{\tau}{4}}=\frac{MB}{MBsin \theta}\)
4 = \(\frac{1}{sinθ}\)
θ = \(sin^{-1}\Big(\frac{1}{4}\Big)\) = 14.47°
Angle through which the magnet is to be rotated is 90 – θ = 75.53°
3. Potential energy decreases. Potential energy is minimum when the magnet is parallel to the field.
U = MBcosθ. When rotated to 0° (to make magnet parallel to the field) Potential energy decreases.