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0 votes
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in Electromagnetic Induction by (26.7k points)

A 100 milli henry coil carries a current of 1 A. energy stored in its magnetic field is

(a) 0.5 J 

(b) 1 A 

(c) 0.05 J 

(d) 0.1 J

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1 Answer

+1 vote
by (26.1k points)

(c) 0.05 J

Explanation :

E = \(\frac{1}{2}LI^2=\frac{1}{2}\times(100\times10^{-3})\times1^2\)  

= 0.05 J.

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