Question

A conductor XY is moving through a uniform magnetic field of intensity B as shown in figure.

1. Name the emf. 

2. The motion of XY towards right side causes an anticlockwise induced current. What will be the direction of magnetic induction in the region A? 

3. The length of the conductor XY is 20 cm. It is moving with a velocity 50 m/s perpendicular to the magnetic e Id. If the induced emf in the conductor is 2V find the magnitudes of magnetic field?

Answer 1

1. Motional emf/induced emf.

2. Applying right hand grip rule at A direction of magnetic field is away from the paper.

3. ε = Blvsinθ, I = 20cm = 20 × 10^-2 m, v = 50m/s, ε = 2v

B = \(\frac{ε}{Iv\,sinθ}= \frac{2}{2\times10^{-2}\times50\times sin90}\)

= 0.2 T