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At a particular temperature, the vapour pressure of two liquids A and B are 120 and 180 mm of Hg respectively. Two moles of A and 3 Moles of B are mixed to form an ideal solution. What is the vapour pressure for the solution?

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A = 120mm of Hg

B = 180 mm of Hg

XA = 2/5

XB = 3/5

PA = P°A x XA

= 120 × 2/5 

= 48 mm of Hg

PB = P°B x XB

= 180 × 3/5 

= 108 mm of Hg

PS = PA + PB

= 108 + 48 

= 156 mm of Hg

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