Question

Find the volume of H₂O that should be added to 300 mL of 0.5 M NaOH so as to prepare a solution of 0.2 M.

Answer 1

M₁V₁ =  M₂V₂

300 × 0.5 =  V₂ × 0.2

V₂ = \(\frac{300\times 5}{2}\)

= 750 mL

H₂O to be added = 750 mL – 300 mL = 450mL