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Calculate the osmotic pressure of 5% solution of urea at 27°C?

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Mass of urea, 

WB = 5 g

R = 0.0821 L atm K-1 mol-1

T = 273 + 27°C = 300 K

Molecular mass of urea, 

MB = 60 g mol-1

V = 100 mL = 0.1L

\(\pi=\frac{W_BRT}{M_B\times V}\)

\(\frac{5g\times0.0821\,L\,atm\,K^{-1}\,mol^{-1}\times\,300\,K}{60\,g\,mol^{-1}\times\, 0.1\,L}\)

= 20.53 atm

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