Question

Solution of sucrose is prepared by dissolving 34.2 g of it in 1000 g of water. Find out the freezing point of the solution, if K_f of water is 1.86 K/kg/mol? (Molecular mass of sucrose is 342 g/mol).

Answer 1

ΔT_f = k_f × m

= 1.86 K kg mol^-1 × \(\frac{34.2\times1000g\,kg^{-1}}{342g\,mol^{-1}\times\,1000g}\)

= 0.186 K

T_f = OK – 0.186 K

Freezing point of the solution = – 0.186 K