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Why does gases always tend to be less solube in liquids as the temperature is raised?

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Dissolution of gases is an exothermic process. It is because of the fact this process involves decrease of entropy (ΔS < 0). Thus, increase of temperature tends to push the equilibrium, Gas + Solvent \(\rightleftharpoons\) Solution; ΔH = -ve in the backward direction, thereby, supressing the dissolution.

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