Question

Consider the following four electrodes 

P = Cu²⁺(.0001 M/Cu(s) Q = Cu²⁺ (0.1 M)/Cu(s) 

R = Cu²⁺(0.01 M)/Cu(s) S = Cu²⁺(0.001 M)Cu(s) 

If the standard reduction potential of Cu²⁺ /Cu is +.34V the reduction potential in volts of the above electrode follows the order.

Answer 1

If the standard reduction potential of Cu²⁺/Cu is +.34V the reduction potential in volts of the above electrode follows the order. i.e.,

Q > R > P