1. Yes.
2. When aqueous CuSO4 solution is electrolysed using Pt electrodes, Cu is deposited at the cathode and O2 is liberated at the anode.
CuSO4 (aq) → Cu2+(aq) + SO42-(aq)
Cu2+ (aq) + 2\(\bar e\) → Cu(s) (at cathode)
H2O(l) → 2H+(aq) + 1/2 O2(g) + 2\(\bar e\) (at anode)
Thus, H2SO4 is formed as the secondary product.