1. \(\frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2}\)
\(\frac{1}{f} = \frac{+1}{10}+\frac{-1}{5}\)
= \(\frac{5-10}{50}\) = \(\frac{-1}{10}\)
f = -10 cm
Effective focal length is negative. Hence this lens is diverging.
2. Effective focal length becomes positive Hence the lens will act as converging.