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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm-1 . Calculate the molar conductivity.

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ΛM \(\frac{k\times1000}{M}\)

\(\frac{0.0248\,S\,cm^{-1}\times1000\,cm^3}{0.2\,mol}\)

= 124 S cm2 mol-1

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