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The photo electronic cut off voltage in a certain experiment is 1.5 V. What is the maximum

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The photo electronic cut off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photo electrons emitted?

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Given V0 = 1.5 V

Since kmax = eV0 

= 1.5 eV

= 1.5 × 1.6 × 10-19 J

= 2.4 × 10-19J.

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