(1). (a) Order = \(\frac{1}{2}+\frac{3}{2}\) = 2
(b) Order = \(\frac{3}{2}+(-1)\) = \(\frac{1}{2}\)
(2). For a 1st order reaction,
k = \(\frac{2.303}{t}log\frac{[R]_0}{[R]}\)
= \(\frac{2.303}{60}log\frac{1.24\,\times\,10^{-2}}{0.20\,\times\,10^{-2}}\)
= \(\frac{2.303}{60}log\,6.2\,min^{-1}\)
k = 0.0304 min-1