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in Chemical Kinetics by (36.2k points)
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1. Identify the reaction order.

  • k= 2.3 × 10-5 L/mol/s
  • k= 3 × 10-4 s-1

 2. Calculate the activation energy. The rate constants of a reaction are 1 × 10-3 s-1 and 2 × 10-3 s-1 at 30°C and 40°C respectively.

1 Answer

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Best answer

1. The reaction order :

  • Second order 
  • First order

2. \(log\,\frac{k_2}{k_1}=\frac{E_a}{2.303R}\) \([\frac{T_2\,-\,T_1}{T_1T_2}]\)

log2 = \(\frac{E_a}{2.303\times 8.314}\)\([\frac{313-\,303}{313\times 303}]\)

log2 = \(\frac{E_a}{2.303\times 8.314}\times\) \([\frac{10}{313\times 303}]\)

\(E_a = \frac{log2\times 2.303\times 8.314\times 331\times 303}{10}\)J

= 57801.71J

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