1. The reaction order :
2. \(log\,\frac{k_2}{k_1}=\frac{E_a}{2.303R}\) \([\frac{T_2\,-\,T_1}{T_1T_2}]\)
log2 = \(\frac{E_a}{2.303\times 8.314}\)\([\frac{313-\,303}{313\times 303}]\)
log2 = \(\frac{E_a}{2.303\times 8.314}\times\) \([\frac{10}{313\times 303}]\)
\(E_a = \frac{log2\times 2.303\times 8.314\times 331\times 303}{10}\)J
= 57801.71J