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in Dual Nature of Radiation and Matter by (26.7k points)
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Figure below shows variation of stopping potential (V0) with frequency(?) of incident radiations for two different metals A and B.

1. Write down the values of work function A and B.

2. What is the significance of slope of the above graph?

3. The value of stopping potential for A and B for a frequency γ01 (which is greater than γ02) of incident radiations are V1 and V0 respectively. Show that the slopes of the lines is equal to \(\frac{v_1-v_2}{γ_{01}-γ_{02}}\).

1 Answer

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1. Work function of A, Φ01 – hν01.

Work function of B, Φ01 – hν02.

2. The slope of the graph gives value of h/e.

3. For the metal A, hν1 = hν01 + eV1 ……(1)

For the metal B, hν1 = hν02 + eV2 ……..(2)

From equation (1) and (2)

01 + eV1 = hν02 + eV2

e(V1 – V2) = h(ν02 – ν01)

\(\frac{h}{e} = \frac{V_1-V_2}{v_{02}-v_{01}}\)

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