1. hν = hν0 + 1/2 mv2
2. Einstein’s photoelectric equation:
a. hν ∝ 1/2 mv2
1/2 mv2 ∝ ν
Hence kinetic energy is proportional to frequency.
b. hν – hν0 = 1/2 mv2
h(ν – ν0) = 1/2 mv2
ν should be greater than ν0 other wise h(ν – ν0) is negative and is not possible.
3. Φ0 =hv0 - 2ev
v = \(\frac{c}{v}=\frac{3\times10^8}{3\times10^{-7}}\) = 1015Hz
a. Φ0 = hν0
ν0 = \(\frac{2\times1.6\times10^{-19}}{6.63\times10^{-34}}\)
= 4.8 × 1014 Hz
b. 1/2 mv2 = h(ν – ν0)
= 6.63 × 10-34(1015 – 4.8 × 1014)
= 3.44 × 10-19J
c. ev0 = h(ν – ν0)
= V0 = \(\frac {h(v-v_0)}{e}\)
= \(\frac{3.44\times10^{-19}}{1.6\times10^{-19}}\) = 5.746 V