**(i)** Mean of player A

=50/4 = 12.5

**(ii)** ** **We should divide the total points by 3 because player C played only three games.

**(iii) **Player B played in all the four games.

**(iv) **To find the best performer, we should know the mean of all players.

Mena of player A = 12.5 Mean of player B = 4.5

Mean of player C = (8+11+13)/3 =32/3 =10.67

Therefore, on comparing means of all players, player A is the best performer.