(i) Mean of player A
=50/4 = 12.5
(ii) We should divide the total points by 3 because player C played only three games.
(iii) Player B played in all the four games.
(iv) To find the best performer, we should know the mean of all players.
Mena of player A = 12.5 Mean of player B = 4.5
Mean of player C = (8+11+13)/3 =32/3 =10.67
Therefore, on comparing means of all players, player A is the best performer.