Let A(x_{1},y_{1}), B(x_{2},y_{2}) and C(x_{3},y_{3}), be the vertices of ΔABC

Let D(-2, 3), E(4, -3) and F(4, 5) be the midpoints of sides BC, CA and AB respectively

Since, D is the midpoint of BC

From (i), (ii) and (iii), we get

From (i) and (iv), we get

x_{1}-4=6 and y_{1}+6=5

x_{1}=10, y_{1}= -1

So, the coordinates of A are (10,-1)

From (ii) and (iv)

x_{2}+8=6 and y_{2}-6=5

x_{2}= -2, y_{2}=11

So, the coordinates of B are (-2,11)

From (iii) and (iv)

x_{3}+8=6 and y_{3}+10=5

x_{3}= -2, y_{3}= -5

So, the coordinates of C are (-2,-5)

Therefore, The vertices of ΔABC are A(10,-1), B(-2,11) and C(-2,-5)

Hence, coordinates of the centroid of ΔABC are