Let A(x1,y1), B(x2,y2) and C(x3,y3), be the vertices of ΔABC
Let D(-2, 3), E(4, -3) and F(4, 5) be the midpoints of sides BC, CA and AB respectively
Since, D is the midpoint of BC
From (i), (ii) and (iii), we get
From (i) and (iv), we get
x1-4=6 and y1+6=5
x1=10, y1= -1
So, the coordinates of A are (10,-1)
From (ii) and (iv)
x2+8=6 and y2-6=5
x2= -2, y2=11
So, the coordinates of B are (-2,11)
From (iii) and (iv)
x3+8=6 and y3+10=5
x3= -2, y3= -5
So, the coordinates of C are (-2,-5)
Therefore, The vertices of ΔABC are A(10,-1), B(-2,11) and C(-2,-5)
Hence, coordinates of the centroid of ΔABC are