1.
2. When we apply an AC signal as input, we get an AC base current denoted by iB . Hence input AC voltage can be written as
Vi = iBr ……..(1)
where ‘r’ is the effective input resistance. This AC input current produces an AC output current (ic) which can ow through a capacitor. Hence the output voltage can be written as
V0 = ic × output resistance
If we take output resistance as RL then v0 becomes
V0 = ic RL
V0 = βACiB x RL .....(2) \(\Big[sinceβ_{AC} =\frac{i_C}{i_B}\Big]\)
AC voltage gain Av = \(\frac{AC\,output\,voltage}{AC\,input\,voltage}\)
i.e. Av = \(\frac{V_0}{V_1}\)
Substituting eq(1) and eq(2),in the above equation we get
Av = \(\frac{β_{AC}i_B\times R_L}{i_Br}\)
Av = \(\frac{β_{AC}R_L}{r}\)
Power gain:
The power gain Ap can be expressed as the product of the current gain and voltage gain. ie. power gain A = βac x Av.