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Draw an angle equal to the difference of two angles given in Fig. 9.5.

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1. Draw an angle ABC equal to ∠DEF (as ∠DEF > ∠PQR), using ruler and compasses. 

2. With BC as one of the arms, draw an angle SBC equal to ∠PQR such that BS is in the interior of ∠ABC as shown in Fig. 9.6. Then, ∠ABS is the require angle which is equal to ∠DEF – ∠PQR. [Note: For making ∠ABS = ∠DEF – ∠PQR, how will you draw ray BS?]

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