Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
461 views
in Amines by (26.2k points)
closed by

1. How is nitrous acid prepared in the laboratory?

2. A student treated methylamine and aniline separately with nitrous acid. What are the products formed in each case? Give chemical equations.

1 Answer

+1 vote
by (26.7k points)
selected by
 
Best answer

1. By treating hydrochloric acid with sodium nitrite, 

2. Methyl amine reacts with nitrous acid to form methyldiazonium salt which being unstable, liberates nitrogen gas quantitatively and forms methanol.

Aniline reacts with nitrous acid at low temperature (273-278 K) to form benzenediazonium salt, a very important compound used in synthetic organic chemistry.

Related questions

0 votes
1 answer
0 votes
1 answer
asked Feb 27, 2021 in Amines by soni02 (26.2k points)
0 votes
1 answer

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...