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Prove that: \(cot^{-1}7+cot^{-1}8+cot^{-1}18=cot^{-1}3\)

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Best answer

We have,

L.H.S. \(=cot^{-1}7+cot^{-1}8+cot^{-1}18\)

\(=cot^{-1}3\) = R.H.S.

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