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A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is –5 dB per km and cable length

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A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is –5 dB per km and cable length is 20 km. The power received at receiver is 10–x W. The value of x is ......

[Gain in dB = 10 log10\(\Big(\frac{P_0}{P_i}\Big)\)]

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1 Answer

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by (26.1k points)

Sound level decreases by 5dB every km so

sound level decreased in 20 km = 100 dB

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