Question

A hydraulic press can lift 100 kg when a mass 'm' is placed on the smaller piston. It can lift ....... kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times keeping the same mass 'm' on the smaller piston.

Answer 1

Using Pascals law

\(\frac{100\times g}{A_2}=\frac{mg}{A_1}\)   ....(1)

Let m mass can lift M₀ in second case then

\(\frac{M_0 g}{16A_2}=\frac{mg}{A_1/16}\)  ....(2)

{Since A = \(\frac{\pi d^2}{4}\)}

From equation (1) and (2) we get

\(\frac{M_0}{16.100}\) = 16

⇒ M₀ = 25600 kg