Question

A particle executes S.H.M with amplitude 0.2m and time period is 24s. The time required for it to move from the mean position to a point 0.1m is

A) 2 s

B) 3 s

c) 8 s

D) 12 s

Answer 1

A) 2 s

Explanations:

Amplitude of particle executing SHM 0.2m. Time period  T=24s

Hence

\(x=0.2sin\omega t\)

\(sin\omega t=\frac{1}{2}=sin \frac{\pi}{6}\)

\(\frac{2\pi}{24} t = \frac{\pi}{6}\)

t= 2s