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in Physics by (15 points)
edited by

pressure is 5× greater than@ surface. If the air pressure on surface of sea is 1.0×1.05 Pa, what depth has the diver reached in the sea?

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1 Answer

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by (105 points)

\(P = \rho gh+P_0\\P=5P_0\\\rho = 1023.6\frac{kg}{m^3}\)

Therefore:

\(h = 4P_0/\rho g = \frac{4\cdot10^5}{1023.6\cdot 9.81}m \approx 39.83m\)

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