Let x, y unit of goods A and B are produced respectively.
Let Z be total revenue
Here, Z = 100x + 120y ....(i)
Subjects to constraints:
Also 2x + 3y ≤ 30 ....(ii)
3x + y ≤ 17 ....(iii)
x, y ≥ 0 ....(iv)
On plotting graph of above constants or inequalities (ii), (iii) and (iv). We get shaded region as feasible region having corner points A, O, B and C.
For coordinate of 'C'
Two equations (ii) and (iii) are solved and we get coordinate of C = (3, 8)
Now, the value of Z is evaluated at corner point as:
Therefore, maximum revenue is Rs 1, 260 when 3 workers and 8 units capital are used for production.