LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
410 views
in Continuity and Differentiability by (37.2k points)
closed by

If y = Peax + Qebx, then show that \(\frac{d^2y}{dx^2}\) - (a+b)\(\frac{dy}{dx}\)+ aby = 0

1 Answer

+1 vote
by (34.6k points)
selected by
 
Best answer

Given,

y = Peax + Qebx

On differentiating with respect to x, we have

\(​​\frac{dy}{dx}\) = Paeax + Qbebx

Again, differentiating with respect to x, we have

\(​​\frac{d^2y}{dx^2}\) =  Pa2eax + Qb2ebx

Now,

LHS = \(​​\frac{d^2y}{dx^2}\) - (a+b)\(​​\frac{dy}{dx}\)+ aby

= 0 = RHS

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...