Since \(\vec{a},\vec{b},\vec{c}\) are mutually perpendicular vectors. Therefore,
Let \(\theta_1\) and \(\theta_2\) and \(\theta_3\) be the angles made by \((\vec{a}+\vec{b}+\vec{c})\) with \(\vec{a},\vec{b}\) and \(\vec{c}\) respectively.
Similarly, we have \(\theta_2=cos^{-1}(\frac{1}{\sqrt{3}})\) and \(\theta_3=cos^{-1}(\frac{1}{\sqrt{3}})\)
\(i.e.,\)
\((\vec{a}+\vec{b}+\vec{c})\) is equally inclined with \(\vec{a},\vec{b}\) and \(\vec{c}\)