Question

If i + j + k. 2i + 5j, 3i + 2j - 3k and i - 6j - k are the position vectors of the points A, B, C and D, then find the angle between \(\vec{AB}\) and \(\vec{CD}.\) Deduce that \(\vec{AB}\) and \(\vec{CD}\) are collinear.

Answer 1

Therefore, \(\vec{AB}\) and \(\vec{CD}\) are parallel vector so \(\vec{AB}\) and \(\vec{CD}\) are collinear and angle between them is zero.