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If \(\vec{a},\,\vec{b},\,\vec{c}\) are three vectors such that \(\vec{a}.\vec{b}=\vec{a}.\vec{c}\) and \(\vec{a}\times \vec{b}=\vec{a}\times \vec{c},\, \vec{a}\neq 0\) then show that \(\vec{b}=\vec{c}.\)

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Given, \(\vec{a}.\vec{b}=\vec{a}.\vec{c}\)

But \(\vec{a}\) cannot be both parallel and perpendicular to \((\vec{b}\,-\,\vec{c}).\) Hence, \(\vec{b}\,=\vec{c}\)

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