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in Definite Integrals by (34.5k points)
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Find the area of the region included between the parabolas y2 = 4ax and x2 = 4ay, where a > 0.

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by (35.0k points)
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Given parabolas are y2 = 4ax .....(i),  x2 = 4ay ...(ii)

Obviously, curve (i) is right handed parabola having vertex at (0, 0), while curve (ii) is upward parabols having vertex at (0, 0).

Shaded region is required region.

For coordinate of intersection point A, (i) and (ii) are solved as

Hence, coordinate of A ≡ (4a, 4a)

Therefore, area of required region = area of OCABO - area of ODABO

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