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Find the approximate value of f (3.02), upto 2 places of decimal, where f (x) = 3x2 + 5x + 3.

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f (x) = 3x2 + 5x + 3

Let x = 3 and dx = 0.02

∴ x + dx = 3.02

By definition, the approximate value of f(x) is

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