Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
368 views
in Derivatives by (36.3k points)
closed by

Show that y = log(1 + x) - \(\frac{2x}{2+x}\), x > - is an increasing function of x throughout its domain.

1 Answer

+1 vote
by (33.5k points)
selected by
 
Best answer

Here,

f(x) = log(1 + x) - \(\frac{2x}{2+x}\) 

[Where y = f(x)]

For f(x) being increasing function

f'(x) > 0

is increasing function in its domain x > - 1.

i.e.,(-1,∞).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...