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Find the equation of tangent to the curve x = sin 3t, y = cos 2t at t =\(\frac{\pi}{4}.\)

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y = cos 2t

∴ \(\frac{dy}{dt}\) = - 2sin 2t


x = sin 3t

∴ \(\frac{dx}{dt}\) = 3 cos 3t

Therefore, equation of tangent at t = \(\frac{\pi}{4}\) i.e., at \((\frac{1}{\sqrt2},0)\) is given by,

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