# Find the equation of tangent to the curve x = sin 3t, y = cos 2t at t = π/4.

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Find the equation of tangent to the curve x = sin 3t, y = cos 2t at t =$\frac{\pi}{4}.$

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Here,

y = cos 2t

∴ $\frac{dy}{dt}$ = - 2sin 2t

Also,

x = sin 3t

∴ $\frac{dx}{dt}$ = 3 cos 3t

Therefore, equation of tangent at t = $\frac{\pi}{4}$ i.e., at $(\frac{1}{\sqrt2},0)$ is given by,