Let F be the fuel cost per hour and v the speed in km/h.
From question,

If t is the time taken by train in covering given distance S km and C the total cost for running the train then,

For maximum or minimum value of C, \(\frac{dC}{dv}=0\)

Also,
⇒ \(\frac{d^2C}{dv^2}=\) 2400 x \(\frac{S}{v^2}\)
⇒ \((\frac{d^2C}{dv^2})_{v=80} > 0\)
Hence, C is minimum, when v = 50 km/hour.