Here,
I = \(\int\frac{2}{(1-x)(1+x^2)}dx\)
Now,
Equating co - efficient both sides, we get
A + C = 2 ...(i)
A - B = 0 ... (ii)
B - C = 0 ...(iii)
From (ii) and (iii)
A = B = C
Putting C = A in (i), we get
A + A = 2
⇒ 2A = 2
⇒ A = 1
i.e., A = B = C = 1