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Find : ∫(5x-2)/(3x^2+2x+1) dx

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Find : \(\int\frac{(5x-2)}{(3x^2+2x+1)}\,dx\)

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The given integral is in the form of, 
\(\int\frac{(px+q)}{(ax^2+bx+c)}\,dx\)

Therefore, we express

(5x - 2) = \(A\frac{d}{dx}\)(1 + 2x +3x2) + B

= A(2 + 6x) + B

Equating the coefficients of x and  the constant term on both the sides, we get

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