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in 3D Coordinate Geometry by (30.9k points)
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Find the points on the line \(\frac{x+2}{3}=\frac{y+1}{2}=\frac{z-3}{2}\) at a distance 5 units from the point P (1, 3, 3).

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Given cartesian form of line is:

\(\therefore\) General point on line is (3μ - 2, 2μ - 1, 2μ + 3)

Since, distance of point on line from P(1, 3, 3) is 5 units.

\(\therefore\) Required point on line is (-2, -1, 3) for μ = 0, or (4, 3, 7) for μ = 2.

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