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in Definite Integrals by (27.3k points)
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Evaluate : \(\int_0^\pi \frac{x\,dx}{a^2cos^2x+b^2sin^2x}\)

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Best answer

Let I = \(\int_0^\pi \frac{x\,dx}{a^2cos^2x+b^2sin^2x}\) ...(i)

Adding (i) and (ii), we get

Divide numerator and denominator by cos2x, we get

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