Question

The value of power dissipated across the zener diode (V_z = 15 V) connected in the circuit as shown in the figure is x × 10^–1 watt.

The value of x, to the nearest integer, is .........

Answer 1

Answer is 5

Voltage across R_S = 22 – 15 = 7V

Current through R_S = I = \(\frac 7{35}\) = \(\frac 15\) A

Current through 90Ω = I₂ = \(\frac{15}{90}=\frac 16\) A

Current through zener = \(\frac 15-\frac 16=\frac 1{30}\) A

Power through zener diode

P = VI

Comments

Ha majaak tha , otherwise this is true one

Answer 2

Answer me to ye hai ki aakh band kar ke 1 se 10 me kuch bhi likh do