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+1 vote
16.6k views
in Physics by (34.4k points)

When two soap bubbles of radii a and b (b > a) coalesce, the radius of curvature of common surface is :

(1) \(\frac{ab}{b-a}\)

(2) \(\frac{a+b}{ab}\)

(3) \(\frac{b-a}{ab}\)

(4) \(\frac{ab}{a+b}\)

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1 Answer

+1 vote
by (34.9k points)
edited by

Correct option is (1) \(\frac{ab}{b-a}\)

Excess pressure at common surface is given by

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